Directions (Q. 1-5): Study the following information carefully and answer the given questions:
There are six cars P, Q, R, S, T and U parked in two rows. Each car has a different colour, viz Red, Yellow, Blue, Green, Orange and White. All the cars are of different prices. T is the most expensive car and is parked exactly opposite the Red car. The lowest priced car is parked exactly opposite the Green car. U, the Orange car, is parked between P and S. R, a Yellow car, is parked opposite P. Q is of Green colour and is parked opposite U. P is not of Blue colour and is more expensive than R, but not more expensive than S or Q.
1. What is the colour of the most expensive car?
1) White 2) Blue 3) Red
4) Yellow 5) None of these
2. What is the colour of the car which is diagonally opposite the White car?
1) Blue 2) Yellow 3) Green
4) Orange 5) None of these
3. Which of the following cars is the second most expensive car?
1) S 2) T 3) Q4) P 5) Can’t be determined
4. Which of the following cars is parked opposite S?
1) P 2) Q 3) T 4) R 5) None of these5. What is the colour of the car which is parked exactly opposite the Yellow car?
1) Green 2) Orange 3) Red4) White 5) None of these
Directions (Q. 31-35): In the questions given below, the relationship between different elements is shown in the statements. These statements are followed by two conclusions. Mark answer
1) if only conclusion I follows.
2) if only conclusion II follows.
3) if either conclusion I or II follows.
4) if neither conclusion I nor II follows.
5) if both conclusions I and II follow.
6. Statements: M < J, J <= R, R = K, K < B
Conclusions: I. K = J II. B > M
7. Statements: P = W, V >= U, W < C, C > V
Conclusions: I. C > P II. U < C
8. Statements: Q >= R, N > M, N <= R
Conclusions: I. Q >= N II. R >= M
(9-10):
Statements: U > X, Y <= Z, C = D, Y <= X, D > Z
9. Conclusions: I. U > Y II. Z >= X
10. Conclusions: I. C > Z II. Y < C
Answer :-There are two possibilities:Possibility (i)
Possibility (ii)
T here a re two possibilities to arrange the cars according to their prices:
Possibility (i) T > S > Q > P > R > U Possibility (ii) T > Q > S > P > R > U
1. 2 2. 1 3.5 4. 3 5. 4
6. (2) Given statements :
M < J ... (i)J <= R ... (ii)
R = K ... (iii)
K < B ... (iv)
Combining all these statements, we get
Hence, conclusion II is true.
7. (5) Given statements :
P = W ... (i)
V >= U ... (ii)
W < C ... (iii)
C > V ... (iv)
Combining all these statements, we get
Again, C > U or U < C is true.
Hence, both conclusions I and II are true.
8. (1) Given statements :
Q >= R ... (i)
N > M ... (ii)
N <= R ... (iii)
Combining all these statements, we get
Hence, conclusion I is true. But conclusion
II (R >= M) is not true.
(9 -10 ):
Given statements:
U > X ... (i)
Y <= Z ... (ii)
C = D ... (iii)
Y <= X ... (iv)
D > Z ... (v)
Combining all these statements, we get
U > X >= Y <= Z < D = C
9. (1)
Hence, conclusion I is true.
T hu s, Z < C or C > Z is true. H ence, conclusion I is true.
Again, Y < C is true. Hence, conclusion II is true.
